If the conversion of Iron ore to iron is represented by Fe2O3(s) + 3CO(g) --gt; 2Fe(s) + 3CO2(g) produces 147 g of iron from 500 g of iron ore, what is the percent yield?Is the answer 29.4% iron ore? Thanks.
Is the answer 29.4% ? no,sorry, it's not Assuming the iron ore is pure Fe2O3 Use the balanced equation. Fe2O3(s) + 3CO(g) -- 2Fe(s) + 3CO2(g) that tells you 1 mole Fe2O3 160g gives 2 moles Fe 112g Use simple proportion 500g Fe2O3 gives 112/160 x 500 350g % yield actual amount / calculated amount x 100 147/350 x 100 42%
