If 3.61 g of aluminum metal reacts completely with excess CuCl2 in a single displacement reaction, what mass of copper metal is produced?I have no clue :(Thank you in advance!
Do you need the work? Or just the answer? The answer is 12.75 gramsI can show you how I did it if you need itEDIT: The reaction is: Al + CuCl2 - AlCl3 + Cu So now you need to balance the equation because there are more chlorine atoms on the left side and you need them to be equalAl + 3CuCl2 - 2AlCl3 + Cu Now you have an equal amount of chlorine, but extra aluminum and copper, so you need to balance those out2Al + 3CuCl2 - 2AlCl3 + 3Cu Now you have that, you can do the stoichiomestryThe molar mass of aluminum is 26.89, so divide the amount of aluminum by that3.61 grams Al / 26.89 grams Al per 1 mol aluminum 0.134 moles of Al There are 2 moles of aluminum for every three moles of copper (up there where the equation is balanced is where I got thisThose coefficients in front of the equation are the moles of that molecule)You need to multiply 3/2 by 0.134 moles to find the moles of copper created(3 moles of copper / 2 moles of aluminum) x 0.134 moles of Aluminum 0.201 moles of copper created Now, just multiply by the molar mass of copper, which is 63.5460.201 moles of copper x 63.546 grams of copper per mol 12.77 moles of copper createdYour answers are always different depending on where you do your rounding, but it's not really a significant amount.
