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Question:

Copper(II) Sulphate and magnsiem to produce what?

Copper(II) Sulphate and magnesium to produce what?

Answer:

Steps: 1.) Get a beaker or vessel that can withhold acid-salt solution for a long period of time. 2.) Get some copper such as wire, copper coins, other copper scraps. 3.)Get household diluted acetic acid (white vinegar) that is double the volume of the copper. 4.) Get a sodium chloride (table salt) that is equal to the volume of the copper. 5.)Mix the diluted acetic acid and sodium chloride in the beaker until the sodium chloride is dissolved. 6.)Add copper to this diluted acetic acid and sodium chloride solution. 7.)Place beaker in a dry dark area. 8.)Wait about four weeks for solution to turn blue and then take out copper pieces. 9.)Wait about another two weeks for water to evaporate. Then you will produce copper sulphate.
Copper (II) Sulfate and Magnesium reaction. CuSO4 + Mg => Cu(2+) + SO4(2-) + Mg (dissolving in water into component ions) Now since magnesium is a more reactive metal, it will reduce the copper to a metal. Cu(2+) + SO4(2-) + Mg => Cu + Mg(2+) + SO4(2-) You may also write the final answer as: Cu + MgSO4, however this is not entirely true since the magnesium sulfate will not precipitate as it is soluble. However the key point here is the exchange of metal ions and oxidation/reduction as per the activity series of metals. Peace.

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