Hi. I would like to build a copper reduction maschine based on electrolysis,with a copper sulfate electrolyt solution...i just do not know if the quantity of refined/recovered copper depends on the voltage or the amperage?I want to refine as much as possible in a short time period and as fast as possible,that is why i would like to know what arangements do i have to have higher voltage or higher amperage???Thank you guys.
on the homestead Depot!! My husband makes use of them for all time. each and every now and returned they're out and he has to reserve them from the two the homestead Depot or he is going to a plumbing hardware grant place.
Since the amperage is the rate of flow of electric current, a higher amperage will cause the copper to plate out faster, other items being equal. One ampere equals 1 coulomb of electrons, or 6.28 * 10**18 electrons passing through the circuit per second. That is, 1 A = 1 coulomb per sec. or 6.28 * 10**18 electrons per second. Avogadro's number (6.023 * 10**23) electrons is equal to about 96,500 coulombs so you can figure out the total electron flow needed to plate out a desired amount of copper. Remember each copper atom requires two electrons to reduce it from a Cu++ ion to a neutral atom. But higher amperage means greater electron flow rate and faster plating out. Higher voltage will cause higher current flow, all other things being equal.
