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Coulomb's Law question?

Two small aluminum spheres, each having mass 0.0250kg, are separated by 80.0cma) How many electrons does each sphere contain? (the atomic mass of aluminum is 26.982g/mol, and its atomic number is 13.) b) How many electrons would have to be removed from one sphere and added to the other to cause an attraction force between the spheres of magnitude 1.00 x 10^4 N (roughly one ton)? Assume that the spheres may be treated as point chargesc) What fraction of all the electrons in each sphere does this represent?

Answer:

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(a) Divide the mass by the atomic mass to calculate the moles of aluminum Multiply that by avocado's number to get the number of aluminum atoms Multiply that by the atomic number to get the number of electrons(b) Coulomb's law F k q1 q2 / r^2Assume both q are equal and oppositeF -k q^2 / r^2 Plug in the force and radius and coulomb constant and solve for qDivide that charge by the fundamental charge to get the number of electrons(c) divide your answer to (b) by the answer to (a) When you get it, post the answer to (c), I'm curiousGood luck!

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