for math i have to find the volume a silo, but i am not sure on how to start the question. After finding the volume i have to find how many pounds of hog fuel weighing at 44.4 lb/(ft^3) can fit inside it assuming that the silo is full. To find that, do i just take the volume and divide it by the mass of the hog fuel?
After finding the volume in ft^3 MULTIPLY by 44.4. (Each ft^3 has 44.4 lbs of matter - 2 fT^3 = 88.8 lbs., 3 ft^3 = 133.2 lbs., ans so on)
d = 12.8 m hci = 10.1 m hco = 10.3 m pi = 3.14 volume silo =pi(d^2/4)(hci + 1/3(hco)) mass = volume * density Edit: Dude, I gave you the formula and all of the values you need to plug in. Just plug in and solve. plug in and solve.
