Domestic electricity costs about 8.75 cents/kwhOne mole of electrons 96,500 coulombs1 kwh 3.6010^6 coulombsAl (0) -gt; Al (+3) +3 electronsI am super confused and have no idea where to start so please also explain how you got your answer so I can learn for other questions like those that may be on the exam- thanks in advance :)
I believe the question is based on electrolysis of Aluminium to obtain pure aluminium to make a can which weighs 16gHence, we must first find the amount of aluminium that is required to make the canAmount of Al needed 16/27 0.592592592 molSince you know that 1.0 mole of Al will release 3 electrons as it turns into an ion, it means that to purify 1.0 mole of Al, the battery will have to move 3 electrons from the anode to the cathode Hence, noof electrons which will be needed to be 'moved' 0.592592592 x 3 1.77777778 Now, we can find the amount of charge by multiplying the amount of electrons with faraday's constant (ie96500) Charge 1.77777778 x 96500 171555.5555 C Now we convert the kWh to Joules8.75 cents / kWh 2.43 x 10^(-6) cents/ J Next we convert the Charge to joulesSince a household is usually provided with a voltage of 240V, Number of joules 240 x 171555.5555 41173333.32 J Hence, we can find the costCost 41173333.32 x 2.43 x 10^(-6) 100.0512 cents $ 1.00 I'm not very sure about the voltage of the householdIt may be different for different countries and suchHope this is still useful :D
RE: are you able to point a lunch bag/field which could keep foodstuff warm for 4 hours? My son doesnt like something 'packable'So we could desire to discover some thing that could desire to keep his lunch warm (or heat a minimum of) for 4 hoursWe'd be packing products like pancakes or spaghetti noodles - not something particularly perishablei attempted a warmth %from a pyrex serving dish, besides the shown fact that it purely stayed.
If you have any of those foam peanuts leftover from packages, you could try to put your food container in a box with that.
