--A wire of resistance 10 ohms is bent to form a circle. Calculate the resistance between two points at the end of the diameter.--I can't understand this. Please show me the steps for finding the answer. I will appreciate your help.
Diameter will shrink the common length in 2 equivalent aspects the resistance of each and every area 10/2 5? Now those 2 5? resistors are in parallel with the aid of a million/R(internet) a million/R1 + a million/R2 a million/R(internet) a million/5 + a million/5 R(internet) 2.5?
If u bend it to form a circle you will have two parralel resistance.becuse you have to semicircle.one of the semicircle is resistance 1 and the other is resistance 2.you have 2 parralel resistance that are both 10 ohms.So the total resistance will be 5. 1/10+1/102/101/R R10/25
5ohms, since it is now in parallel? Maybe?
Theoretically - can, but practically u need to check. You consider the the maximum possible measurable length between the two measuring point, as total length of conductor and take twice the cro-sectional area. In practice length is reducing and diameter is increasing so the resistance will reduce. The diameter will be the length here.
