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Question:

Engineerin problem very interesting and i need help? pls can any one click this?

The air gap in a magnetic circuit is 1.5 mm long and cross sectional area is 2500 mm^2, Calculate:(a) the reluctance of air gap and (b) the mmf to send a flux of 800 muWb across the air gap.

Answer:

a)RL/(uA) upemeability of magnetic field Llength of air gap AArea Have to check the units i lazy to check b)MMFRxflux
The above answer is super close. But because this is an air gap and not the magnetic material itself, there will be fringing effects. Since it is an air gap, ur 1 and but the cross section dimensions will increase by 5%. Therefore, the reluctance is: R (1.5 mm)/((4pi*10 ^-7)*(1.05)^2*(2500mm^2)) [you will need to change all mm to meters because of the permubility of air]. with the conversion factors, I get about 433.075 Webers. Next is easy, mmf is the reluctance times flux. I am not sure what your flux is. It should be in Tesla or Webber/m^2

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