1/2 [3( t + 2) - (2 - t)] + 1 7 Please show step by step process
notice the +t in this step (its like having -1 x things in the bracket
You have to start with brackets/parentheses next 1/2 [3(t+2) -(2-t)]+1 7 so multiply 1/2 by everything in the brackets 3/2(t + 2) - 1/2 (2 - t) + 1 7 Next you need to get rid of the parentheses so you need to multiply both terms inside 3/2t + 3/2(2) which becomes 3 and 1/2(2) which becomes negative 1 - negative 1/2 t getting 3/2t + 3 - 1 + 1/2 t + 1 7 combining like terms 4/2t + 3 7 - 4/2 just becomes 2 2t + 3 7 subtract 3 from both sides 2t 4 divide by 2 to isolate the variable t 2 if you substitute t 2 back in to your original equations and use order of operations, it checks out!!
First you will have to work the equations with the parentheses first, then work inside the brackets. So for this equation: 1/2[3(t+2)-(2-t)]+17 you workout the by factoring the numbers in front of the parentheses. which is 3 and -1: 1/2[3t+6-2+t]+17 combine the like terms inside the bracket: 1/2[4t+4]+17 factor out the 1/2 in front of the bracket: 2t+2+17 combine like terms: 2t+37 then solve for t: 2t4 (subtracting 3 from both sides) t2 (divide by 2 from both sides) Note: that there are multiple variations to solving this equation, i.e. multiplying by 2 from both sides to cancel out the 1/2 which was in front of the bracket.
