find a number which is nine less than twice the additive inverse?
Inverses are 2 numbers that combine to be the identification component, that's 0 for addition. So the additive inverse is the alternative. actual, 9 under two times the additive inverse of n would be -2n - 9
Let's call the number x. The additive inverse is by definition, -x (because x + -x 0). This leads us to the following equation: x + 9 -2x which will give us x -3.
9 less than twice the additive inverse of what? If our original number is x, then: the additive inverse gives us: -x twice tells us to multiply that by 2, which gives us: -2x 9 less than tells us to subtract 9 from that, which gives us: -2x - 9 So, whatever your original number was, multiply by -2 and subtract 9 to get your answer.
