chemistry quiz tomorrow. please help!
If the ore is 60% iron(III) oxide (Fe2O3) then there is a maximum of 60% * 50 kg available 30Kg The % of Iron in iron 3 oxide is as follows. Mass of iron/ Mass of whole substance 111.8/159.8 x 100 69.96% So the mass you could get from it is 0.6996 * 30 Kg 20.99 Kg Hope this helps.
