Fill in the blankAn aluminum wire having a cross-sectional area of carries a current of 7.00 A Find the drift speed of the electrons in the wireThe density of aluminum is (Assume that one electron is supplied by each atom.) Round your answer to three significant figuresTake the charge of the electron to be and the Avogadro's constant to be mm/s
By Formula I neAV I 7.00 A n charge density overall density A cross sectional area V Drift Speed Rearranging, V 7/density(1.610^-19)Area of Cross Section Put the values and get the answer
[Ar] 3d10 4s2 4p4 Two electrons in the 4p orbital are unpaired The reason is because of the properties of how electron shells fillIf you know what the Aufbau principle is, or Hund's rule, those can be used to explain the order that the electrons fillTHERE ARE 2 UNPAIRED ELECTRONS, NOT 4! The 4p orbital looks like this [i!][i][i] where the i and ! are electrons
