Gear torque problemA pinion gear is fitted with a big gear 2 times larger than it. If a torque is applied to the pinion, then the torque of the big gear is two times?
A pinion gear is fitted with a large gear 2 times larger than the gear. If one moment acts on the pinion, then the gear is two times longer than the pinion:Suppose the gear A and gear B bite, the gear A radius is Ra, and the gear B radius is Rb.
Torque ratio Na:Nb= (Fa*Ra): (Fb*Rb) = Ra:RbOr: Na= (Ra/Rb) *Nb.A conclusion is thus drawn:The ratio of the torque each of the two pairs of gear teeth is equal to their radius ratioIn this question, A is the big gear, B is the pinion, and the Ra/Rb=2 is: Na= (Ra/Rb) *Nb=2*Nb.
The two gear interaction in the bite, is a pair of equal and opposite forces respectively in two gear and counter force. In gear on the A force is Fa; in gear on the B force is Fb; Fa=Fb.The torque A on the gear Na=Fa*Ra; the torque B on the gear Nb=Fb*Rb
