Please help me answer these Genetics problems. These are the problems that was assigned in the previous exams, but the professor doesn't provide the answer keys or a review session to go over these.Pigment in the mouse is produced only when the C allele is present. Individuals of the cc genotype have no color. if color is present, it may be determined by the A, a alleles. AA or Aa results in the agouti color, while aa results in the black color. In 3 crosses between agouti females whose genotypes are unknowns and males of the aacc genotype, the following phenotypic ratios were obtained. Female 1: 8 agouti 8 colorlessFemale 2: 4 agouti 5 black 10 colorless
interior the 1st bypass AACC x aacc, discern a million will produce all AC gametes and discern 2 ac. Your F1 will all be AaCc. As all have the C allele they are going to be pigmented and as they're Aa they're going to all be agouti. Your F1 bypass is AaCc x AaCc. each and each discern can produce 4 gametes AC, Ac, aC, ac. To get all the genotypes you would be able to desire to entice a 4 x 4 Punnett sq.. each and each column and each and each row has between the 4 gametes in it and the cells comprise the blended genotypes. in case you count type up your genotypes you will discover 9 comprise the two A and C, those are agouti, 4 comprise cc, and all of those would be white regardless of the genotype at A, 3 comprise aa and C, those will all be black. So your phenotypic ratio would be 9:4:3 agouti: white: black the subsequent 3 crosses are all attempt crosses - you employ a recessive discern to artwork out the genotype of the different discern. a million. As lots of the offspring are colourless, you be attentive to that the two mothers and dads carry the c allele, as you pick cc for colourless mice. As there are no black mice, there is not any a allele interior the mum, as no aa offspring are produced. The bypass is AACc x aacc. woman gametes are AC or Ac and male gametes are all ac, offspring are the two AaCc or Aacc. 2. Is the opposite of bypass a million. There are black offspring so mom would desire to hold an a allele to furnish black mice, as there are no colourless ones, there is not any c allele interior the mum. you could write down the bypass and the F2 effect now. 3. This time all hues are produced, so the mum would desire to hold the two a and c alleles. Her genotype is AaCc, she would be able to offer 4 gametes as interior the 1st bypass and you will artwork out the resultant genotypes and phenotypes interior the F2.
