Sb2S3(s) + 3 Fe(s) 2 Sb(s) + 3 FeS(s)When 16.5 g Sb2S3 reacts with an excess of Fe, 9.84 g Sb is produced. What is the percent yield of this reaction?______________%
yes they will fit, the offset is larger wich is good it puts the rim further from the brake caliper, the only thing you need to worry about is when you turn the wheel all the way and have weight in the car(like 2 pasangers) do the tires rub on anything
surely. Your front and rear suspension is designed so as that an imaginary line drops from the suited middle of the struts on the instant all the way down to the middle patch of the tires. If this geometry is replaced the genuine middle of the tire patch sits away (street area) from the designed middle. This does 2 significant issues: #a million. this is totally now complex on all wheel bearings. #2. With incorrect off-set wheels interior the front each and each time you step on the brakes at the same time as turning the guidance wheel will attempt to self middle or jerk the guidance wheel on the instant forward.
I continually do.i'm very beneficiant approximately giving stars,,,,*.on each occasion i hit upon any ineterstiing a ques, I make advantageous that i famous guy or woman itthe akser merits it.!!! right this is one for you!.*
From the reaction it is know that 1 mole of stibnite (Sb2S3) will react with excess iron to form 2 moles of antimony (Sb). Use the atomic weights to from a ratio to calculated theoretical recovery value. Which would be: 339.68 grams Sb2S3 gives 243.5 grams Sb; So, 16.5 g is X g of antimony. Solve and get X 11.8 grams Sb. But it says that only 9.84 grams is actually recovered! To find the % yield, divide 9.84g (actual result) by the calculated theoretical recovery value of 11.8 g and multiply by 100. Yield (9.84/11.8) * 100 Yield 83.2%
