Hey so I tried this problem myself but I got it wrong, so I am coming here for some assistance. I don‘t necessarily need an answer (it would be nice) but I would like to know how to get to my answer. So please if someone could help it would be appreciated!Using the reaction below:3CuO + 2NH3(g) → 3Cu(s) + N2(g) + 3H2O(l)In one reaction, 3.0 kg of copper (II) oxide is heated at 564 °C in a 5.0-L vessel. The pressure of N2 is 0.19 bar after 7.0 minutes.Question: What is the average rate of N2 production in mol/min during the 7-minute interval?How many moles of copper (II) oxide consumed in the 7-minute interval?____Okay so this is what I did:Copper (II) oxide molsnPV/RTn(.19)(5.0)/(.0821*837K)n0.0138 molsSo then I divide that by 3 to get mols of N2 (4.6E-3) then I divide that by 7 min to get mols/min. I get 6.58E-4 for the first part and I assume the answer to the second part is just 0.0138 mols (1.38E-2) but I get it wrong when I use those values!What exactly did I do wrong, how do I correct it!
All of the bloodless air intakes are the same except for color or whatever like that. So far as being loud i would say it might be the equal as well, watching for horsepower as a rule most horsepower obtain that you would be ready to consider would roughly be around 5-10 horses sure i know they declare they are able to add up to 25-35 horses its bull does not add that so much. To even in all likelihood get that so much you can desire a new exhaust process, new headers, and then you definately also want a tuner so which you can make the whole thing work in perfect harmony so it all relies how a lot you wish to have to position in hondas are cram holes you can put in additional than 50,000 dollars into one and make roughly about 450 horses and thats only for the quarter mile so sure every bloodless air consumption is the same in case you look at that means you just cant discontinue at having a cold air intake you want the whole thing else to make it work the best way you want it to. So good luck and glad tuning
You have heard wrong. Your car came from the factory with a cold air intake. What makes you think you need two of them? If you add another cold air intake what will you do with the one that came on the car? How do you plan to hook both of them up? Aftermarket cold air intakes have no water drains. How do you plan to deal with that? You didn't know your stock air intake system has a water-drain between the lest front fender and the left front inner-fender. If your car is under factory warranty you'll loose it by adding a second cold air system. You've never seen what an aftermarket air-cleaner does to a mass air flow sensor have you?
If you buy a performance intake which is an aftermarket kit it increases mileage and power. I had a 2002 chevy and added an advanced air intake system cost around $290. Mileage increased about 3 miles per gallon. Power is really nice. A very noticeable increase in mileage and performance.
Convert 0.19bar to atm: 0.19 bar 0.1875 atmosphere [standard] That is from my unit conversion progrmme 564°C 837K Solve for moles N2 by using gas law equation PV nRT 0.1875*5 n * 0.082057*837 n 0.9375/68.69 n 0.01365 mol N2 produced. That is how many moles of N2 that was produced in 7 minutes. Rate of production of N2 0.01365/7 0.00195 mol per minute I see no reason to divide by 3 The question does not ask for rate of production of N2 per minute per kilogram CuO. It only asks for rate of production of N2 per minute. Question 2: From the balanced equation: 3 CuO + 2 NH3(g) 3 Cu(s) + N2(g) + 3 H2O(l) 3mol CuO produce 1 mol N2 To produce 0.01365 mol N2 you require : 0.01365*3 0.041 mol CuO
