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Question:

help! Supposedly easy Electron charging process?

A 19 g piece of aluminum that was originally electrically neutral is given a charge of +7.6 ?C.(a)How many electrons were removed from the aluminum in the charging process?I found that A is 4.75 x 10^13 electrons by dividing the charge (7.6x10^-6) by how much each electron is worth(1.60x10^-19)What fraction of the electrons originally in the aluminum were involved in the charging process?I don't know how to do this problemcan someone please help me out? Thank you.

Answer:

Well, you know that each aluminum atom has 13 electronsAlso, you can find out the molar mass, thus you can find out how many moles of Aluminum you haveEach mole contains 6.02x10^23 atoms, and as mentioned before each atom of aluminum has 13 electronsMultiply to get the number of electronsThen it is just a matter of finding the ratio of two numbers.
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