Aluminum can react with dioxygenHow much Al2O3 can be formed by 50 g of aluminum and an excess of dioxygen.
First of all, dioxygen is simply called oxygenIn its elemental state oxygen is naturally two oxygens per molecule :) Start with a balanced chemical equationYou know aluminum and oxygen are reacting to form Al2O3 so you can write the followingAl + O2 - Al2O3 Balance this to give 4 Al + 3 O2 - 2Al2O3 Then you want to convert between mass of aluminum and mass of aluminum oxideWhen doing this make sure your units cancelThe mol/g conversions are from the molar masses on the periodic table, and the mol/mol conversions come from the balanced chemical equation50 g Al (1 mol Al / 26.98 g Al) (2 mol Al2O3 / 4 mol Al) (101.96 g Al2O3 / 1 mol Al2O3) This leaves units of grams of aluminum oxideYou then simply multiply by everything on top and divide by everything on bottom to get 94.4774 g aluminum oxideWatch significant figures so that the final answer is 94 g aluminum oxideTwo significant figures in the answer because the initial grams of aluminum was limited to two signifcant figures.
