I want to multiply current 10times for a second or two. So, is there any easy way to do that without using a high power transformer?Thanx.!
You could use a large capacitor. A resistor or constant current source charges the capacitor for e.g. 10s at 1mA. Then you can discharge it at 10mA for about 1s. If you need a lot of current and a lot of voltage, a battery will do the same. Lead acid batteries will give you insane currents (hundreds to thousands of amps) for seconds to minutes. That's how your car's starter gets powered.
Current can be multiplied 10 times when using a current transformer with a ratio of 10, such 50/5 amperes. Donut type CTwith a burden of 15 VA.
Current from what kind of source, into what kind of load? Does the load take AC or DC?? What voltage does it need?? Why do you have to multiply the current? You can get clever with things like bucking switcher supplies to take 120 volts in and get 12 volts out at about 10x the current, but if your load isn't DC it doesn't help you. Edit:? 30 A @ 8 V isn't much, just 240 watts.? You can probably get this out of an old computer power supply; just re-wind (or add an extra winding in series with) the 5 volt winding on the toroid transformer to get 8 volts.? You may have to get fancy to get it to stay on (lots of the newer supplies want to be loaded, and want special signals to run) but with common supplies putting out 400 watts and more you should have no trouble.? The only issue is that you won't get 50 or 60 Hz, but since you didn't say your load has any particular frequency requirement I'll offer this as a possibility.
If your output is 8V ac, then a transformer is unfortunately your best bet. You can get real fancy and do a switching power converter/inverter (sort of like the inverters that convert 12V dc in vehicles to 120V ac), but that solution is outside the ability of most designers. You would lose a lot of hair and if you're lucky, it MIGHT be cheaper. ************************************** I'm assuming you want to conserve power and increase I by a factor of 10 while decreasing V by a factor of 10? Remember; P V*I A switching regulator will allow you to transform power from one form to another very efficiently (often 90% or better). It uses an inductor switched cleverly between the source and load. This is used in most modern power supplies instead of a transformer (like laptop supplies, cell phone chargers etc.) Your question is a little vague you can increase current 10 times by reducing the load impedance (resistance) by a facto of 10. Ohms law VI*R or IV/R. Reduce R by 10, increase I by a factor of 10. Hope this helps, Dave
