I have a single phase AC motor of 1440 rpm that i can reduce upto 20rpm by gear arrangement pl help me by saying gear sizes.................
There is no way to do that. This is an induction motor. A VFD (Variable Frequency pressure) won't work as brought up through lunchtime_browser. You will have got to use a gearbox with close to any motor to do that. In case you use an induction motor (squirrel cage or AC motor), it's possible to control a 3 section motor to shrink speeds with the aid of making use of a VFD, that reduces the voltage and alterations the frequency, however handiest within limits. These may also be programmed to a fixed speed, however not so sluggish as a hundred and twenty RPM. The cooling could additionally have got to be addressed (fan too slow). Single segment (cut up segment) motors are extra constrained, whether or not making use of a centrifugal switch or not. You generally want a DC motor if you happen to insist on no gearbox. The variable pace controller to swimsuit this motor is just set to the velocity you want. If you need a particular velocity it desires a velocity controller with pace sensor and feedback. Be aware that the mechanical power is the made from RPM and torque. The torque is kind of the equal, as it is decided through the present ranking. However with 120 RPM from a 1440 RPM motor the velocity is just one/12 so the power is only 1/12. Utilizing a gearbox increases the torque and reduces the pace so the power is more or less the identical. There are gearmotors for a wide variety of output RPM. A bicycle hub motor might suit if the power is to your variety. An additional thought is a stepper motor, which can run at these low speeds, however it does need a controller (driver) and energy provide..
* I presume that you do not want to procure standard Reduction gear box which are normally available in engineering market.Are available in various reduction ratios. * If you intend to built your own reduction gear box then I would suggest to use Worm and Worm gear. You will have to do calculation for determining dimensions, number of teeths, pitch of thread in worm etc Midhat Luqman
W1/W2=N2/N1 Meaning your angular velocity input(W1) divided by output (w2) is equal to number of teeth of the output (n2) divided by number of teeth of input (n1). Im notsure how your gears are currently set up, but use that formula to solve for what youre looking for.
