Question:
how do i calculate the mass percent of iron for the iron ores Fe2O3, Fe3O4, and FeCO3?
Iron is mined from the earth as iron ore. Common ores include Fe2O3 (hematite), Fe3O4 (magnetite), and FeCo (siderite).I need help calculating the mass percent for each one of these please!
Answer:
Assume a 100-g sample of each ore. Convert that amount to moles by dividing by the ore's respective molecular weight, and then take the ratio of iron in the ore, and the ore itself. Then multiply by the molecular weight of iron to find the weight of iron in that 100 g sample. The mass percent would be massFe / massSample * 100%. 100 g Fe2O3 (159.7 g/mol Fe2O3) 0.626 mol Fe2O3 (2 mol Fe / 1 mol Fe2O3) 1.25 mol Fe (55.85 g/mol) Fe 69.8 g Fe Mass percent Fe 69.8 / 100 * 100% 69.8% Fe 100 g Fe3O4 (231.5 g/mol Fe3O4) 0.432 (3 mol Fe / 1 mol Fe3O4) 1.30 mol Fe (55.85 g/mol Fe) 72.4 g Fe Mass Percent Fe 72.4 / 100 * 100% 72.4% Fe I'm sure you can do the last one.
There is 2 Fe, not 1 Fe. Thus, 55.85 x 2 111.7 --- 111.7/159.7 x 100% 69.9 % Same with Fe3O4: 3 Fe, not 1 Fe. Thus, 55.85 x 3167.55 --- 167.55/231.55 x 100% 72.4 % I hope this helps.
If all the three are present together in one sample, you can not derive by calculation. Total Fe and FeO can be analysed wet chemically. Determination of Fe3O4, Fe2O3 and FeCO3 need phase analysis (XRD Technique) to determine.
Yes, they are the same system. If you drive the car and hit the brakes you will not stop until you hit someone or some thing substantial.
hi i don't know your car but nearly all vehicles have a thing called tandem break systems where the pipes are split diagonal front wheel to opposite back wheel or just front to back.So if you are going to drive you will have only half the breaking performance and fluid loss .All in all is it worth the risk i would say not
Assume a 100-g sample of each ore. Convert that amount to moles by dividing by the ore's respective molecular weight, and then take the ratio of iron in the ore, and the ore itself. Then multiply by the molecular weight of iron to find the weight of iron in that 100 g sample. The mass percent would be massFe / massSample * 100%. 100 g Fe2O3 (159.7 g/mol Fe2O3) 0.626 mol Fe2O3 (2 mol Fe / 1 mol Fe2O3) 1.25 mol Fe (55.85 g/mol) Fe 69.8 g Fe Mass percent Fe 69.8 / 100 * 100% 69.8% Fe 100 g Fe3O4 (231.5 g/mol Fe3O4) 0.432 (3 mol Fe / 1 mol Fe3O4) 1.30 mol Fe (55.85 g/mol Fe) 72.4 g Fe Mass Percent Fe 72.4 / 100 * 100% 72.4% Fe I'm sure you can do the last one.
There is 2 Fe, not 1 Fe. Thus, 55.85 x 2 111.7 --- 111.7/159.7 x 100% 69.9 % Same with Fe3O4: 3 Fe, not 1 Fe. Thus, 55.85 x 3167.55 --- 167.55/231.55 x 100% 72.4 % I hope this helps.
hi i don't know your car but nearly all vehicles have a thing called tandem break systems where the pipes are split diagonal front wheel to opposite back wheel or just front to back.So if you are going to drive you will have only half the breaking performance and fluid loss .All in all is it worth the risk i would say not
Yes, they are the same system. If you drive the car and hit the brakes you will not stop until you hit someone or some thing substantial.
If all the three are present together in one sample, you can not derive by calculation. Total Fe and FeO can be analysed wet chemically. Determination of Fe3O4, Fe2O3 and FeCO3 need phase analysis (XRD Technique) to determine.
