i don't understand how to solve squared bracketsexamples:(7x+5)?(3b-4)?
properly those are parentheses not brackets. ok in case you have ever carried out distributive sources do the comparable ingredient yet sq. it. right here i'm going to help: (3x-5)? -(3x+2)? [(3x*3x)-(5*5)]-[(3x*3x)+(2*2)] [(9x)-(25)]-[(9x)+(4)] Um properly you recognize algebra, i don't sense like fixing it
It means that everything inside the parentheses () gets squared (multiplied by itself). (7x+5)? (7x+5)(7x+5) Then you solve that by using FOIL (First Outer Inner Last). (7x+5)(7x+5) 49x? + 35x +35x + 25 49x? +70x + 25
First, your examples are not quite accurate. I can think of two possibilities: If the question was to expand a squared bracket, you can use FOIL (7x+5)^2 (7x+5)(7x+5) 49x^2 + 35x + 35x +25 49x^2 + 70x +25 If you want to solve a squared brackets, then you need to have an equation. That means the squared bracket must be equal to something. Let assume (7x+5)^2 9. What number do you have to square to get nine? One of them is 3. This means 7x+53. The other number is negative 3. So, you really have two solutions. If 7x+53, then 7x-2. Therefore, x -2/7. I let you solve 7x+5 -3.
