this question is very easy guys just take ur time to find the answer,ciao.
Aluminum has an electron transfer requirement (oxidation state) looking for 3 electrons, while the sulfate portion of the sulfuric acid only has two electrons to donateBy balancing the electron transfer requirements for this reaction, the resulting formula is: (3) H2SO4 + (2) Al Al2(SO4)3 + 3 H2 (gas)In order to balance the equation, it requires 3 moles of sulfuric acid to react with 2 moles of Aluminum, producing 1 mole of Aluminum Sulfate and 3 moles of Hydrogen (gas).
So, 1 mole of Al2(SO4)3 has TWO moles of AluminumFigure out how many moles of Al2(SO4)3 are in 8 gm and multiply by 2 to get moles of AlTHen multiply that by atomic mass of Al to get massThus, 8.0 g x 342 g/mol 0.023 moles of Al2(SO4)3 moles of Al 2 x 0.023 0.046 moles Al mass Al 0.046 moles Al x 27 g/mol 1.24 grams of Al in 8.0 g of Al2(SO4)3
