how many graams of flourin are produced
it's too many to readi read the first oneMy answer is curiosity.
a lot of riddles, i couldn't read them all but i know the 8th one for death: you ask either one of them what door would the other robot tell me to go through? and you;d just go through the opposite one.
Who am i? 1a flamingo? 2different time zones? 6a cookie? The Hobbit 3Sex? Others 2a woman shoots the mans wife6silence
Death: 7: They were both fish who's bowl got knocked over 8: Ask them both the same question: Which door leads to life? They'll both say the same thing Who am I? and What is it?: 3: A penis? The Hobbit: 8: An egg Others: 4: Its daytime 5: Put caps on the jugs 6: Silence
Be careful how you type the formulaFluorine (not flourin) is F2, not FIf you leave it F in your equation, the equation is unbalancedYou need to use the information you are given to determine the limiting reagentTo do that divide the amount of each reactant by it's molecular weightThat will give you moles of eachThis gives you 2.61 moles of aluminum fluoride and 1.5 moles oxygenIf you have 2.61 moles of aluminum fluoride, you would need 1.96 moles of oxygen (I took 2.613/4 which is the mole ratio to get this number), which you don't haveSo, oxygen is the limiting reagent Then reconfigure the equation using the adjusted number of moles from the limiting reagentSince there are 1.5 moles of oxygen, you are reacting 2 moles of aluminum fluoride with it and producing one mole of aluminium oxide and 3 moles of fluorine3 moles of fluorine (F2), or 113.98g would be producedA good way to check yourself is to go back and make sure the mass of your reactants equals the mass of the productsThat is how I saw your equation was off a littleIn this case 215.94g 215.94g so you are goodI tried to break everything down for you, I hope this helps!
