2 Al+ 3 ZnCl2 3 Zn + 2 AlCl3A mass of 45.0 grams of aluminum will react with how many grams of zinc chloride? show/explain please
2Al(s) + 3CuSO4 (aq) - Al2(SO4)3 + 3Cu(s) Did you notice any copper metal deposited near the leak? Did the blue solution become less blue? Look up the reduction potentials for Al and Cu
2Al + 3ZnCl2 - 3Zn + 2AlCl3 45.0g ?? g Simply use the unit-factor method and apply a couple of conversion factors45 g Al x (1 mol Al / 27.0g Al) x (2 mol AlCl3 / 2 mol Al) x (133.5 g AlCl3 / 1 mol AlCl3) 223 g AlCl3 The first conversion factor converts from grams of Al to moles of AlThe second determines the moles of AlCl3This one is easy, since the ratio is 2:2 or 1:1, as indicated by the balanced chemical equationThe third conversion factor takes us from moles of AlCl3 to the mass of AlCl3The answer is rounded to three significant digits to match the precision of your original mass of Al.
