How do you test for lead(II) ion and aluminum ion?
It should truly be his choice whether he wants it to be or notAsk him what he wants between Titanium, Tungsten and White goldTell him the benefits and cons of each, and then give him a horror story about when they weren't able to cut a ring off while you were working in the ER lolAt least whats what I would do to try and push him towards my wayIt is the ring he will be stuck wearing for the rest of his life, so let him choose, whether he wants to or notTell him he can pick it out of a hat for all you careAnd if he truly will not choose, then don't get him the single kind he doesn't wantgo with Titanium Tungsten or white goldYou could also consider platinum depending on your budget.
this question requires some recollection for me (i have done some experiments on this 2 ions)there are 2 common ways of testing for the lead(II) ion.first is the use of aqueous sodium hydroxide and the use of aqueous ammonia.for this question i absolutely recommend the use of aqueous ammonia because the use of aqueous ammonia doesn't help - in the use of aqueous sodium hydroxide,both ions here will dissolve so u can't tell the differencehere is the procedure for the test using an aqueous ammonialet say i have some white powderstep 1:using a spatula,scoop some of that powder and drop them into a test tubestep 2:add a few drops of water (if possible add distilled water,if not,tap water will do) to obtain an aqueous solutionstep 3:to the solution add a few drops of aqueous ammoniastep 4:watch the formation of a white precipitateafter step 4 u can draw 2 conclusions1)if the white precipitate dissolves after some shaking then the powder contains aluminium(III) ions(this results in a colorless solution.) 2)if the white precipitate doesn't dissolves after some serious shaking then the powder contains lead(II) ionsits that simple.
