How many atoms of phosphorus are in 5.00 mol of copper(II) phosphate?
copper II phosphate is Cu3(PO4)2 Each mole of copper II phos. contains 2 moles of phos. atoms so 5 x 2 = 10 moles of phos. atoms 10 x 6.022 x10^23 = 6.022 x10^24 atoms of phos.
Cu3(PO4)2 is the formula so that means you have 2P per mole of it 5 mol x 2P/mol x (6.03 x 10^23 atoms) = answer
