How many grams of sulfuric acid can be obtained from 400 grams of iron ore if the ore is 80% FeS? The reactions involved are given below. Assume each reaction is 100% efficient. 4FeS + 7O2 -----gt; 2Fe2O3 + 4SO3 2SO3 + O2 -------gt; 2SO3SO3 + H2O ------gt; H2SO4
The sewer pipe should be below the toilet. The water pipe is the one you need to find. Unless your water supply comes from street level and goes to a basement, or if you're in an apartment building, chances are that the water pipes come up from below the toilet as well.
First you would find how much ore is 80% of 400g which is 320g. Now you will need to convert that to moles which is basically 320 /(87.91g/mol). Next use the moles you have to find the moles of S03 created based on the ratio of the first equation. (Mole is the coefficient in from the the substances.) Ex lets say you came out with four moles of FeS that would yield four moles of SO3 and based on stoichiometric balancing that would give you 4 moles of H2SO4. Lastly convert that moles back to grams of H2SO4 by multiplying it by the gram formula mass of H2SO4 or (98.09g/mol). Thus your ans should be 357.1g. But I find that your second equation seems incorret as well your first. As it should be S02+ O2 - SO3 and the first equation should yield SO2 not SO3.
The soil stack or vent is usually in the wall directly behind the toilet. This is usually a 4 diameter pipe and is made of plastic in newer homes and metal in older homes.
The soil stack or vent is usually in the wall directly behind the toilet. This is usually a 4 diameter pipe and is made of plastic in newer homes and metal in older homes.
The sewer pipe should be below the toilet. The water pipe is the one you need to find. Unless your water supply comes from street level and goes to a basement, or if you're in an apartment building, chances are that the water pipes come up from below the toilet as well.
First you would find how much ore is 80% of 400g which is 320g. Now you will need to convert that to moles which is basically 320 /(87.91g/mol). Next use the moles you have to find the moles of S03 created based on the ratio of the first equation. (Mole is the coefficient in from the the substances.) Ex lets say you came out with four moles of FeS that would yield four moles of SO3 and based on stoichiometric balancing that would give you 4 moles of H2SO4. Lastly convert that moles back to grams of H2SO4 by multiplying it by the gram formula mass of H2SO4 or (98.09g/mol). Thus your ans should be 357.1g. But I find that your second equation seems incorret as well your first. As it should be S02+ O2 - SO3 and the first equation should yield SO2 not SO3.
