How many Kilograms of iron can be recovered from 639 kilograms of the ore Fe2O3?
MW Fe2O3 55.8*2 + 16.0*3 159.6 g Moles mass /MW 639 kg / 159.6 639,000g / 159.6 4003.8 moles Each mole of Fe203 yields 2 moles of Fe. 4003.8 moles Fe203 2*4003.8 8007.5 moles of Fe. mass moles x MW 8007.5 * 55.8 446,812 g 446.8 kg There are 446.8 kg of iron in 639 kg of iron ore.
Some pretty good arguments.
