An electric generating plant boils water to produce high- pressure steam. The steam spins a turbine that is connected to the generator.Can anyone help me with this please? I used pv=nRT and got 4.53 mol but im not sure how to get the liters of water out of that.
( 1 ) You need the volume of the boiler. ( 2 ) The Ideal Gas Law does not work well for such a high pressure. ( 3 ) Assume boiler volume, VB, is 100,000 L. ( 4 ) Steam Table for superheated steam at 5.0 Mpaa. ( 50 atm. ) and 400 C gives a steam specific volume of 0.05784 cu. m. per kg. or 57.84 L. per kg. ( 5 ) Steam mass, m , is: m = ( VB ) /( v ) m = (100,000 L.) / ( 57.84 L. per kg. ) m = 1729 kg. steam / water needed ( 6 ) If the liquid water is saturated liquid at 5.000 Mpaa.( 50 atm. ) , liquid specific volume from steam table is 1.286 L. per kg. V = ( m ) ( v ) V = ( 1729 kg. ) ( 1.286 L. / kg. ) = 2223 L. ---------------------------- You would need 2223 L. of liquid water at 50 atm. vaporized at 50 atm. and superheated to 400.0 C to fill boiler with a volume of 100,000 L.
You do not have enough information to solve this question. How large is the boiler tank. Also, the ideal gas law is an erroneous method for steam, unless the steam is over 800 Celsius. For this set of conditions, you will make a 10% error by using the ideal gas law.
