How many mL of 6 M KOH are required to supply potassium ion in the alum formed from 1.1 g of aluminum?
alum is KAl(SO4)2.12H2O each mole has 1 mole of Al 1 mole of K use molar mass to find moles of Al: 1.1 g Al 27 g/mol 0.0407 moles of Al at that 1 mole of Al to 1 mole of K 0.0407 moles of Al requires 0.0407 moles of K find volume 0.0407 moles of K 6 moles / Litre KOH 0.00679 litres of KOPH your answer, rounded to 2 sig fig would be 6.8 ml of KOH however, since the 6M KOH has only 1 sig fig, you are likely expected to round your answer off to 7 ml of KOH
