36How many electrons are shared by the atoms in the compound N2?A2 B6 C4 D8ENone of the Above//I'm guessing it's 6 but I'm not sureAny answer and brief explanation?What is the correct name for the following?P4O5Apotassium (IV) pentoxide Btetraphosphorus pentoxide Cdiphosphorus tetroxideDphosphorus pentoxideENone of the AboveAl2O3Aaluminide oxide Baluminum oxide Caluminum trioxide Daluminum (III) oxideENone of the Above//Quite confused with the roman numerals inside the parenthesisWhich ones are correct? Any help appreciated :)
Nitrogen has five valence electronsThree of which for each atom are shared in a triple bondTherefore, we can say that six electrons are involved in bonding, three from each atomThe remaining two valence electrons for each nitrogen exist as a nonbonding lone pairIf it existed, P4O5 would be called tetraphosphorous pentoxideIt would be a compound of two nonmetals and named using the Greek prefix methodIt is unlikely that P4O5 is an actual compoundThere does exist P2O5 and P4O10, but there is no indication that P4O5 existsWhen I do workshops for chemistry teachers, I always suggest that they use real compounds and real reactions in questions and problemsThat doesn't seem to be the case hereAl2O3 is simply called aluminum oxideAluminum(III) oxide would not be incorrectThe Roman numeral indicates the oxidation number of the metal in the Stock system of nomenclatureIn the Stock system you first write the name of the metal, then you add a Roman numeral corresponding to the oxidation number of the metal, and then write the name of the anionThe Roman numeral may be omitted for metals that exhibit only one oxidation numberThe question is poor because there are two possible correct answersBoth aluminum oxide and aluminum (III) oxide must be counted correct even though aluminum oxide is the more common name for Al2O3.
