My professor gave us the following:1roll of Reynonlds Wrap Heavy Duty Aluminum18.0 in wide, 500.0 ft long and 0.94mil thickThe cost $48.98and I'm not sure how to figure it out
length * width * thickness = volume (with some unit conversions) Mass = volume * density (look up the density of aluminum) convert mass to moles. convert moles to atoms Divide the cost by the number of Al atoms.
You have : ---------------- V = aluminum volume in one roll = ( L ) ( W ) ( t ) V = ( 500 ft ) ( 1.5 ft ) ( 0.94 mil ) ( 1 in / 1000 mil ) ( 1 ft/12 in ) V = 0.05875 ft^3 m = aluminum mass = ( d ) ( V ) m = ( 168 lbm/ft^3 ) ( 0.05875 ft^3 ) = 9.87 lbm m = ( 9.87 lbm ) ( 453.6 g / 1.0 lbm ) = 4477 g n = moles of aluminum in one roll = m / M n = ( 4477 g ) / ( 27 g/mol ) = 165.8 moles Al N Al atoms = ( n Al ) ( NAVO ) N Al atoms = ( 165.8 mol ) ( 6.022 x 10^23 atoms / mol ) N Al atoms = 998.5 x 10^23 Al atoms C* = cost per atom = cost of aluminum roll / number of aluminum atoms in one roll C* = ( 4898 cents ) / 998.5 x 10^23 atoms ) C* = 4.91 x 10^-23 cents per Al atom --------------- Please award Best Answer to the most correct and most helpful response to your question. C* =
