How much iron can be obtained from 1kg of iron ore that is iron (II) oxide, FeO?
It would be (mass of ore)*(molar mass of iron) / (molar mass of FeO) 1 kg * 55.8 / 71.8 0.78 kg of iron.
Theoretically, ratio of masses Fe:O is 56:16 7:2 Thus we can obtain 7/9 kg of Iron from 1 kg FeO
