how to control the inputs and outputs of aluminum?
The volume of the nickel block is 20/8800 cubic metres The volume of the aluminium block is 20/2700 cubic metres 20/8800 - 20/2700 1/440 - 1/135 440-135/59400 305/59400 0.0051 cubic metres The question seems wrong if its a non calculator paperIn the proper exam, you certainly won't get a question like this.
Density Mass / Volume , or D M/V You're given D and M, you need to find V for the two blocks of metalFor nickel: V M/D (20 kg)/(8800 kg/m?) 1/440 m? volume of nickel block For aluminium: V M/D (20 kg)/(2700 kg/m?) 1/135 m? volume of aluminium By inspecting the volumes, you should see that the aluminium block has the greater volumeDifference 1/135 - 1/440 you calculate it
Not sure what your question itIf you are making Al from bauxite, the inputs are the ore (mostly Al2O3), elecricity, temperature of the molten bath, and the molten salt used for the electrolysisThe outputs are the amount of Al metal, the O2 gas, and the purity of the Al (among other things)IF you are talking about the inputs to a solid piece of Al that you want turned into something specific (like an airplane wing strut or a beverage can or a window frame), the inputs are the alloy content (different Al alloys are used for different things), the starting structure, the amount of hot/cold work, and the heat treatmentThe outputs are the shape, the physical and chemical properties, and the amount of scrap (among other things)hope this helps.
