For example, channel 8 is bent into a circle with an inner diameter of 1030 and an opening outwards. How do you calculate the lofting length?
Bend 90 degrees, the diameter of 300MM, is this material: a straight line length is pi (D-T) (d--- pipe diameter, t--- thickness).
Is generally a narrow face half the diameter of the channel calculation, you can use this method to calculate the diameter + channel narrow surface, can calculate the total length of the 1030+43=1073, you can press the layout can be. Can experiment first, the length of the extension of several tens of millimeters, so as to avoid errors, according to the actual error can be processed, I do not know if I understand, there is a little more, ha ha
Divide the line 16 from 0.1.2.3 to 16. Calculate the two diameter elbow lofting: Yn=r cos alpha when 0 DEG n below 90 DEG Yn=1/2 alpha (d-2t alpha) cosWhen 90 degrees less than or equal to 180 degrees when n < alpha Yn=1/2dcos alphaIn the formula, the Yn--- expansion graph has a circumferential length equal to the curve coordinate value;R--- auxiliary circle radius;D--- diameter of round tube;T--- plate thickness;Alpha n--- auxiliary circumferential equal angle; tube of 300mm diameter,N optional 16 alpha 1=360 degrees, /16=22.5 degrees, 2=45 degrees, 3=67.5 degrees, 4=90 degrees, 5=112.5 degrees, 6=135 degrees, 7=157.5 degrees, 8=180 degreesFormula: Y0=1/2 (d-2t) cos0 degrees =0.5 (d-2t)Y1=1/2 (d-2t) cos22.5 degrees =0.4619 (d-2t)Y2=1/2 (d-2t) cos45 degrees =0.3536 (d-2t)Y3=1/2 (d-2t) cos67.5 degrees =0.1913 (d-2t)Y4=1/2 (d-2t) cos90 degrees =0Y5=1/2 dcos112.5 degrees =-0.1913dY6=1/2 dcos135 degrees =-0.3536dY7=1/2 dcos157.5 degrees =-0.4619dY8=1/2 dcos180 degrees =-0.5d
