Typically, water runs through the baseboard copper tubing and, therefore, fresh hot water is constantly running through the piping. However, consider a pipe where water was allowed to sit in the pipe. The hot water cools as it sits in the pipe. What is the temprature change, (ΔT), of the water if 204.5 g of water sat in the copper pipe from part A, releasing 1559 J of energy to the pipe? The specific heat of water is 4.184 J/(g??C).Express your answer to four significant figures.Water‘s heat of fusion is 80. cal/g , its specific heat is 1.0calg??C, and its heat of vaporization is 540 cal/g .A canister is filled with 370 g of ice and 100. g of liquid water, both at 0 ?C . The canister is placed in an oven until all the H2O has boiled off and the canister is empty. How much energy in calories was absorbed?Express your answer to two significant figures and include the appropriate units.
The copper pipe problem can't be answered without knowing the mass of the pipe. ------------------------ (80. cal/g) x (370 g ice) 29600 cal to melt the ice (1.0 cal/g??C) x (370 g + 100 g) x (100 - 0) ?C 47000 cal to heat the liquid to its boiling point (540 cal/g) x (370 g + 100 g) 253800 cal to vaporize the liquid 29600 cal + 47000 cal + 253800 cal 330400 cal 3.3 x 10^2 kcal
Typically, water runs through the baseboard copper tubing and, therefore, fresh hot water is constantly running through the piping. However, consider a pipe where water was allowed to sit in the pipe. The hot water cools as it sits in the pipe. What is the temprature change, (ΔT), of the water if 204.5 g of water sat in the copper pipe from part A, releasing 1559 J of energy to the pipe? The specific heat of water is 4.184 J/(g??C). Express your answer to four significant figures. I can't figure this out. I get 1.822 .c but it's not right.
