i have a homework to do and its about Heati have answered it already but i need to be sure if its correct.q: By accident, 20g of aluminum at 275°C is dropped to a 25g of water at 80°CHow much steam is produced? anyone knows the solution for this problem?please use the equation QmLvwhere, Q - heat m - mass Lv - heat of evaporation 2.25x10^6 J/kgthanks!!!!
The heat leaving the aluminum all goes into heating the water from 80C to 100C and then evaporating x grams of water: M_alu C_alu (275 - 100) M_water C_water 20 + x Lv Solve for x: x ( M_alu C_alu (275 - 100) - M_water C_water20) / Lv (20g 0.897 J/(g C) 175C - 25g4.18J/(g C) 20C) / (2.2510^3 J/g) 0.47 gram
