I would like to ask how the calculation of the amount of steel in this stairs is very grateful
The first picture is the reinforcement chart of the staircase 1 (TB1), and the second and the third are the chart. The map has no important use for reinforcement.
This section of the chart, there is no marked ② the length of the two ends of the steel bend, had to rely on their own ladder beam TL height minus two protective layer calculation; ② both ends of the bar into the ladder TL tilt length and ② steel net Cross the length of the skew should be used 'hooks the law' law calculation.
For example, the net span of the ladder plate is long = √ [3600 ? + (1950-TL cross section high) ?].
② both ends of the reinforcement into the ladder TL inclined length = √ (300 ? + 150 ?) and then by a protective layer, and then reduced (step width and TL wide difference). ---- here is an approximation.
The figure is to show the hook, ① and ② bar is a hook, ④ No. tendons do not need to set the hook. General staircase hook is 180 degrees.
There are a lot of uncertainties in the picture you give. Ladder beam size, protective layer thickness and so no, so only a rough calculation.
First calculate the staircase reinforcement slant 4450m.
TB1 Reinforcement:
① the number of tendons 1.6 / 0.1 = 16 single reinforced length 4.45 + 12.5 * 0.012 (12.5 * 0.012 for the hook length) line density of 0.888kg / m
② No. 16 reinforced single piece length 4.45 + 0.4 * 2 + 12.5 * 0.012 linear density of 0.617kg / m
④ No. 4.45 / 0.25 = 19 a total of 38 single-length steel length of 1.6m line density of 0.222kg / m
??? Steel weight = steel count * single reinforced length * line density
