I need help solving this, please show your work!10 PTS FOR BEST ANSWER!!
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The chemical reaction is this: 2Al(OH)3 + 3H2SO4 - Al2(SO4)3 + 6H2O The key thing is the molar ratio that Al(OH)3 and H2SO4 react inIt is a 2:3 ratiowe need to know the moles of Al(OH)3: 1.50 g / 78.0027 g/mol 0.01923 mol - I'll keep one guard digit Now, we determine the moles of H2SO4 needed: 2 is to 3 as 0.01923 mol is to x x 0.028845 mol Next, determine the volume of H2SO4: 0.028845 mol divided by 1.65 mol/L 0.01748 L Changing to mL and rounding off to three sig figs gives 17.5 mL for your answer.
