... initial temperature of the water or the initial temperature of the aluminum? Why?
Let's say the aluminum starts out at a higher temperature than the water. The aluminum cools down by 1°C, which means it loses energy (Q = mcΔT, where ΔT = 1°C). That energy goes to the water, warming it up. Since Q is the same for both water and aluminum, and m is the same for both, all that matters is the heat capacity c. Water has a higher heat capacity than aluminum, so for the same Q it must have a smaller ΔT. This process continues until both have reached the same T. From the above paragraph, you should be able to figure out if the final T is closer to the initial water temp or the original aluminum temp.
The correct equation is: dQ = m*c*dT As dQ (substitute of thermal potential) and mass are the comparable, the equation may well be rewritten as: c*dT=consistent So a cloth with a decrease specific warmth skill could have a much better improve in temperature. The question has already suggested this yet now all of us be attentive to they are inversely proportional. to that end: c of aluminium/c of copper = dT of aluminium / dT of copper 0.22/0.092 = proportionality consistent = 2.39 So copper would be 2.4 circumstances warmer than aluminium (or aluminium would be 0.40 two circumstances warmer than copper).
