If you are given 0.5423 grams of aluminum foil, what is the maximum mass (in grams) of alum (K2SO4·Al2(SO4)3·24H2O) you could synthesize?
1mole of K2SO4·Al2(SO4)3·24H2O , whose molar mass is 948.78 g/mol contains 2 moles of Aluminum 26.98 g/mol 53.96 grams Al 0.5423 grams (948.78 g/mol alum) / (53.96 grams Al) 9,5352 grams of alum your answer, rounded to 4 sig figs is 9,535 grams of alum
Aluminum is from group 3 and there for has 3 electrons in its outer shell and desires 5 to fill itit is going to react with any aspects from group 5 that desire aluminum's 3 electrons.
