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Ions and their electrons worksheet?

Determine the charges on the following elements based on their locations on the periodic table using the knowledge gained during the Are You Charged? lesson:1Fluorine, F 7 2Magnesium, Mg 12 3Aluminum, Al 13 4Sodium, Na 11 5Nitrogen, N 7 6Zinc, Zn 30 7Hydrogen, H 1 8Argon, Ar 18 9Barium, Ba 56 10Sulfur, S 16 This is my worksheet, i need help!

Answer:

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i could use decal-paper-not too high pricedin any different case, it is not too high priced to have somebody print on the mug or mugs for youit is going to look lots extra expertThey do it at Walmart for $12.ninety six according to mug.
Before we go on, i am not aware of the method used to find oxidation state in the are you charged? lesson but il try to give u the answers anywayalso if the numbers beside the elements are their atomic numbers, fluorine's supposed to be 9 and not 7For fluorine, it is in the 7th group and the goal of these elements is to achieve an octet configuration( 8 electrons in outer shell)So how many electrons does fluorine need to gain to achieve this? F 7-8 -1 for magnesium it is in the 2nd group and has just 2 electrons in outer shell, so it wants to release those two electrons instead of gaining 6so we have Mg +2 aluminum is in the third group so it has a +3 oxidation energy sodium is in the 1st so it has a +1 nitrogen is in the 5th but since nitrogen is much closer to the octet state, it wants to gain electrons so we have N 5-8 -3 zinc is a transition element in the 2B(12) group (see periodic table) it has two outer shell electrons that it wants to release so it has a +2 oxidation stateHydrogen has a +1 oxidation state Argon has a complete octet configuration so it does not need any electron nor does it need to lose anyso it has a oxidation of 0not reactivebarium is in the second group so it has a +2 and finally sulfur is in the 6th group and needs two electrons to achieve an octet state so S 6-8 -2 For elements in the middle such as carbon and the rest, it could be either way depending on the compound that they exist in.
Before we go on, i am not aware of the method used to find oxidation state in the are you charged? lesson but il try to give u the answers anywayalso if the numbers beside the elements are their atomic numbers, fluorine's supposed to be 9 and not 7For fluorine, it is in the 7th group and the goal of these elements is to achieve an octet configuration( 8 electrons in outer shell)So how many electrons does fluorine need to gain to achieve this? F 7-8 -1 for magnesium it is in the 2nd group and has just 2 electrons in outer shell, so it wants to release those two electrons instead of gaining 6so we have Mg +2 aluminum is in the third group so it has a +3 oxidation energy sodium is in the 1st so it has a +1 nitrogen is in the 5th but since nitrogen is much closer to the octet state, it wants to gain electrons so we have N 5-8 -3 zinc is a transition element in the 2B(12) group (see periodic table) it has two outer shell electrons that it wants to release so it has a +2 oxidation stateHydrogen has a +1 oxidation state Argon has a complete octet configuration so it does not need any electron nor does it need to lose anyso it has a oxidation of 0not reactivebarium is in the second group so it has a +2 and finally sulfur is in the 6th group and needs two electrons to achieve an octet state so S 6-8 -2 For elements in the middle such as carbon and the rest, it could be either way depending on the compound that they exist in.

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