1. iron is generally produced from iron ore through the reactionFe2O3(s) + CO(g) ?→ Fe(s) + CO2(g) .If 2.6 kg of Fe2O3 are available to react, how much CO is needed?Answer in units of mol012 (part 2 of 3) 1.0 points2.How much Fe can be produced? Answer in units of mol? Help please !! #1 is 49
HI, something that has not been mentioned the add mark on the transmission is ONLY 1 pint not like the add mark on the motor oil which is 1 quart Now if it is not on the stick you can start with 1 quart of the proper ATF. good luck tim
First you need to balance the equation: Fe2O3(s) + 3CO(g) ?→ 2Fe(s) + 3CO2(g) Then solve for moles of CO 2.6 kg Fe2O3 X 1000g/kg X 1mol Fe2O3 / 159.69 g Fe2O3 X 3mol CO / 1 mol Fe2O3 49 mole CO Part 2 is done the same way, just solving for Fe: 2.6 kg Fe2O3 X 1000g/kg X 1mol Fe2O3 / 159.69 g Fe2O3 X 2mol Fe / 1 mol Fe2O3 33 mole Fe
the only way in is where the dipstick goes but if you need to add it its leaking somewhere
the only way in is where the dipstick goes but if you need to add it its leaking somewhere
HI, something that has not been mentioned the add mark on the transmission is ONLY 1 pint not like the add mark on the motor oil which is 1 quart Now if it is not on the stick you can start with 1 quart of the proper ATF. good luck tim
First you need to balance the equation: Fe2O3(s) + 3CO(g) ?→ 2Fe(s) + 3CO2(g) Then solve for moles of CO 2.6 kg Fe2O3 X 1000g/kg X 1mol Fe2O3 / 159.69 g Fe2O3 X 3mol CO / 1 mol Fe2O3 49 mole CO Part 2 is done the same way, just solving for Fe: 2.6 kg Fe2O3 X 1000g/kg X 1mol Fe2O3 / 159.69 g Fe2O3 X 2mol Fe / 1 mol Fe2O3 33 mole Fe
