2Fe2O3 + 3C ---gt; 4Fe + 3CO2A mixture of 30 kg of Fe2O3 and 5.0 kg of C was heated until the reaction was completed. Calculate the maximum mass of iron that can be obtained from these masses of reactants.Could a kind soul help me out?
moles Fe2O3 30,000 g /159.694 g/mol187.8 the ratio between Fe2O3 and C is 2 : 3 moles C required 187.8 x 3 /2281.7 actual moles of C 5,000 g / 12.011 g/mol416 so C is the limiting reactant and Fe2O3 is in excess the ratio between C and Fe is 3 : 4 moles Fe 416 x 4 /3555 mass Fe 555 mol x 55.847 g/mol3.10 x 10^4 g 31 Kg
