Alum (KAl(SO4)212H2O) forms from the potassium ions, hydrated aluminum ions ([Al(H2O)6]3+), sulfate ions, and water.Now when I balance that equation, I get: K+ + [Al(H2O)6]3+ + 2[SO4]2- + 6H2O -gt; KAl(SO4)212H2ONow I'm wondering if the water of the reactant side and the product side should cancel each other outWould I get something like this: K+ + [Al(H2O)6]3+ + 2[SO4]2- -gt; KAl(SO4)2 + 6H2OI don't know how I should leave itI'm confused with the whole hydrated shell idea when it comes to equationsSo can somebody give me the correct formula please?!?! Thanks in advance.
