A wire is 1.5 m long and has a diameter of 1.5 mm. The stretch modulus of the wire is 6.2 x 10^10 N/m^2. If a force of 400 N is applied to end of the wire then the increase in length of the wire is???please help, thanks
The stretching of wire by longitudinal force: If F force applied across the crosectional area A of wire of radius r and lenght L then the wire elaogates in the dirextion of force Stress P = F / A A = pi* r^2 = (1.5/2)*10^-3 = 7.5 *10^-4 m^2 strain produced = dL / L = increase in length / original L Young's modulus or elastic (stretch) modulus for the maretial, within elastic limits, Y = stress/strain strain = stress / Y dL = F * L / A * Y = F * L / pi (r^2) * Y dL = 400* 1.5 / 3.14 (7.5 *10^-4)^2 * 6.2*10^10) meter dL = 0.005479 * meter dL = 5.479 millimeters increase in length
