A circular solenoid contains 100 turns of wire and carries a current of 2 amps. Its radius is 1 cm and its length is 10 cm. Calculate the magnetic flux through one turn of the wire making the solenoid.
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From Ampere's circuital law integral H dot dl current enclosed in this case H dl I enc H Ienc / dl There are 100 turns per 10 cm or 10 turns per cm which is the same as 1 mm per turn that corresponds to one single turn. Since you want to enclose only one turn then dl 1mm 1E-3 m and Ienc 2 A So you can calculate H from the equation above. Now, this is the magnetic field of flux area density. Go ahead and multiply H by the cross section of the coil and you have your answer. You probably will have to multiply by the magnetic permeability of the material to obtain this in other magnetic units.
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