A large Cylindrical corn silo on a farm in Nebraska is 24 feet high and has a base with radius of 8 feet. How much corn could the silo contain if it was completely full?
Volume = πr? * h = π8? * 24 = 1536π ft? ≈ 4825.49 ft? of corn.
((pie) x 8^2) x 24 is your answer the answer will be in feet^2 the answer is this: pie x 64 x 24 pie x 1536 4825.4863 feet^2
Assuming okorder gives you 1 cubic foot = 0.803563949632 bushel [
Volume of a cylinder= base area x perpendicular height = area of the circle base by height of the silo = ( pi x radius x radius) x height = 3.141 x 8 x 8 x 24 = 4824.58 cubic feet I cubic foot = 0.8 bushel Therefore 4824.58 x 0.8 = 3859.66 bushels of corn
That depends on the packing fraction of the corn. V = h x pi x r^2 = 24 * 3.141 * 8^2 = 4824 cubic feet. If the packing fraction is 95% due to the space between the ears of corn, you'd get 4582 cubic feet into the silo. This, of course, is neglecting the volume of a half sphere of radius 8 at the top :) If the corn is ground into meal or flour before being placed in the silo, your packing fraction will approach 100%.
